What is the derivative of y=(5x^3)/3-x+7e^x ?

The derivative of y=(5x^3)/3-x+7e^x is 5x^2-1+7e^x

What is the first derivative of y=(5x^3)/3-x+7e^x ?

The first derivative of y=(5x^3)/3-x+7e^x is 5x^2-1+7e^x

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derivative of

y = \frac{5 x ^{3}}{3} - x + 7 e^{x}

5 x^{2} - 1 + 7 e^{x}

Solution steps

\frac{d}{d x} (\frac{5 x ^{3}}{3} - x + 7 e^{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{5 x ^{3}}{3}) - \frac{d x}{d x} + \frac{d}{d x} (7 e^{x})

\frac{d}{d x} (\frac{5 x ^{3}}{3}) = 5 x^{2}

\frac{d x}{d x} = 1

\frac{d}{d x} (7 e^{x}) = 7 e^{x}

= 5 x^{2} - 1 + 7 e^{x}

- 2 x^{3} + 23 x^{2} - 33 x - 108, [0, x]

t \frac{d y}{d t} = 2 t e^{t} - y + 6 t^{2}

\int 2 e^{6} d x

\int 1 + x d x

x \to 8 lim (\frac{x}{x ^{2} - 64})

What is the derivative of y=(5x^3)/3-x+7e^x ?
The derivative of y=(5x^3)/3-x+7e^x is 5x^2-1+7e^x
What is the first derivative of y=(5x^3)/3-x+7e^x ?
The first derivative of y=(5x^3)/3-x+7e^x is 5x^2-1+7e^x