Solution
Solution
Solution steps
Apply the Product Rule:
Popular Examples
maclaurin (1+x^2)^{(-3)/2}maclaurin y^'=((3y^2+9))/(2xy)sum from n=1 to infinity of 1/(2+n)limit as x approaches 0 of (1-e^{2x})/xintegral from-infinity to 8 of re^{r/2}
Frequently Asked Questions (FAQ)
What is the derivative of x^6e^{2x^3} ?
The derivative of x^6e^{2x^3} is 6e^{2x^3}x^5+6e^{2x^3}x^8What is the first derivative of x^6e^{2x^3} ?
The first derivative of x^6e^{2x^3} is 6e^{2x^3}x^5+6e^{2x^3}x^8