What is the integral from-infinity to 0 of 1/(7-5x) ?

The integral from-infinity to 0 of 1/(7-5x) is diverges

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integral from-infinity to 0 of 1/(7-5x)

\int_{- \infty}^{0} \frac{1}{7 - 5 x} d x

diverges

Solution steps

\int_{- \infty}^{0} \frac{1}{7 - 5 x} d x

Compute the indefinite integral:

\int \frac{1}{7 - 5 x} d x = - \frac{1}{5} ln ∣ 7 - 5 x ∣ + C

Compute the boundaries:

\int_{- \infty}^{0} \frac{1}{7 - 5 x} d x =

diverges

= diverges

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What is the integral from-infinity to 0 of 1/(7-5x) ?
The integral from-infinity to 0 of 1/(7-5x) is diverges