What is the tangent of f(x)= 2/x ,\at x=-2 ?

The tangent of f(x)= 2/x ,\at x=-2 is y=-1/2 x-2

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tangent of f(x)= 2/x ,\at x=-2

tangent of

f (x) = \frac{2}{x}, at x = - 2

y = - \frac{1}{2} x - 2

Solution steps

Find the tangent point:

(- 2, - 1)

Find the slope of

f (x) = \frac{2}{x} : \frac{df ( x )}{d x} = - \frac{2}{x ^{2}}

Compute the slope of

f (x) = \frac{2}{x}

x = - 2 : m = - \frac{1}{2}

Find the line with slope m=

- \frac{1}{2}

and passing through

(- 2, - 1) : y = - \frac{1}{2} x - 2

y = - \frac{1}{2} x - 2

y^{^{''}} + y = 2^{x}

\int_{1}^{3} (x^{5} + \frac{1}{4 x ^{5}}) d x

\int 10 x e^{- 5 x} d x

f (x) = \frac{3}{x}, (- 5, - \frac{3}{5})

n = 0 \sum \infty sin (\frac{1}{n})

What is the tangent of f(x)= 2/x ,\at x=-2 ?
The tangent of f(x)= 2/x ,\at x=-2 is y=-1/2 x-2