What is (\partial)/(\partial x)(-3x^2-4x) ?

The answer to (\partial)/(\partial x)(-3x^2-4x) is -6x-4

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(\partial)/(\partial x)(-3x^2-4x)

\frac{\partial}{\partial x} (- 3 x^{2} - 4 x)

- 6 x - 4

Solution steps

\frac{\partial}{\partial x} (- 3 x^{2} - 4 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{\partial}{\partial x} (3 x^{2}) - \frac{\partial}{\partial x} (4 x)

\frac{\partial}{\partial x} (3 x^{2}) = 6 x

\frac{\partial}{\partial x} (4 x) = 4

= - 6 x - 4

x \to 0 + lim (1 - ln (x))

\frac{3}{( s ^{2} + 1 ) ( s ^{2} + 9 )}

\int \frac{3 x ^{2} + 2 x + 1}{x ^{2} ( x + 1 )} d x

\int - sin^{2} (x) + cos^{2} (x) d x

\int_{1}^{3} \frac{x ^{2} - 1}{x} d x

What is (\partial)/(\partial x)(-3x^2-4x) ?
The answer to (\partial)/(\partial x)(-3x^2-4x) is -6x-4