What is the sum from n=0 to infinity of 1/((2n-1)^2) ?

The sum from n=0 to infinity of 1/((2n-1)^2) is converges

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sum from n=0 to infinity of 1/((2n-1)^2)

n = 0 \sum \infty \frac{1}{( 2 n - 1 ) ^{2}}

converges

Solution steps

n = 0 \sum \infty \frac{1}{( 2 n - 1 ) ^{2}}

Apply Series Comparison Test:

converges

= converges

\frac{d}{d x} (ln (cos (9 x)))

x \to 5 lim (\frac{sin ( 5 π )}{3})

n = 1 \sum \infty \frac{40}{4 ^{n}}

\frac{\partial}{\partial x} (x^{2} + 8 y^{2} + 9 z^{2} - 7)

\frac{d}{d x} (f (x) (5 x^{2} + 3))

What is the sum from n=0 to infinity of 1/((2n-1)^2) ?
The sum from n=0 to infinity of 1/((2n-1)^2) is converges