What is the limit as x approaches 0+of (e^x+x)^{1/4} ?

The limit as x approaches 0+of (e^x+x)^{1/4} is 1

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limit as x approaches 0+of (e^x+x)^{1/4}

x \to 0 + lim ((e^{x} + x)^{\frac{1}{4}})

1

Solution steps

x \to 0 + lim ((e^{x} + x)^{\frac{1}{4}})

Plug in the value

x = 0

= (e^{0} + 0)^{\frac{1}{4}}

Simplify

= 1

m = 2

y^{^{'}} = \frac{( y ^{4} - 1 )}{x y ^{3}}

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What is the limit as x approaches 0+of (e^x+x)^{1/4} ?
The limit as x approaches 0+of (e^x+x)^{1/4} is 1