What is (d^2)/(dydx)(sin(x^2y^2)) ?

The answer to (d^2)/(dydx)(sin(x^2y^2)) is 2y(-2x^3y^2sin(x^2y^2)+2xcos(x^2y^2))

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(d^2)/(dydx)(sin(x^2y^2))

\frac{d ^{2}}{d y d x} (sin (x^{2} y^{2}))

2 y (- 2 x^{3} y^{2} sin (x^{2} y^{2}) + 2 x cos (x^{2} y^{2}))

Solution steps

\frac{d ^{2}}{d y d x} (sin (x^{2} y^{2}))

\frac{d}{d y} (sin (x^{2} y^{2})) = cos (x^{2} y^{2}) \cdot 2 x^{2} y

= \frac{d}{d x} (cos (x^{2} y^{2}) \cdot 2 x^{2} y)

\frac{d}{d x} (cos (x^{2} y^{2}) \cdot 2 x^{2} y) = 2 y (- 2 x^{3} y^{2} sin (x^{2} y^{2}) + 2 x cos (x^{2} y^{2}))

= 2 y (- 2 x^{3} y^{2} sin (x^{2} y^{2}) + 2 x cos (x^{2} y^{2}))

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What is (d^2)/(dydx)(sin(x^2y^2)) ?
The answer to (d^2)/(dydx)(sin(x^2y^2)) is 2y(-2x^3y^2sin(x^2y^2)+2xcos(x^2y^2))