What is the solution for 12x^3-3y^2sqrt(x^4+1)y^'=0 ?

The solution for 12x^3-3y^2sqrt(x^4+1)y^'=0 is y=\sqrt[3]{6sqrt(x^4+1)+c_{1}}

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12x^3-3y^2sqrt(x^4+1)y^'=0

12 x^{3} - 3 y^{2} x^{4} + 1 y^{^{'}} = 0

Solution steps

12 x^{3} - 3 y^{2} x^{4} + 1 y^{'} (x) = 0

Solve separable ODE:

\int \frac{2}{5 x} d x

\int (sec (4 x) - cot (4 x)) d x

\frac{d}{d x} (sin (2 π x))

\frac{\partial}{\partial x} (x^{3} + y^{2})

x^{2} y^{^{''}} + 15 x y^{^{'}} + 49 y = 0

What is the solution for 12x^3-3y^2sqrt(x^4+1)y^'=0 ?
The solution for 12x^3-3y^2sqrt(x^4+1)y^'=0 is y=\sqrt[3]{6sqrt(x^4+1)+c_{1}}