What is the solution for (dy)/(dx)+4y=-x ?

The solution for (dy)/(dx)+4y=-x is y=-(4x-1)/(16)+(c_{1})/(e^{4x)}

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(dy)/(dx)+4y=-x

\frac{d y}{d x} + 4 y = - x

y = - \frac{4 x - 1}{16} + \frac{c _{1}}{e ^{4 x}}

Solution steps

\frac{d y}{d x} + 4 y = - x

Solve linear ODE:

y = - \frac{4 x - 1}{16} + \frac{c _{1}}{e ^{4 x}}

y = - \frac{4 x - 1}{16} + \frac{c _{1}}{e ^{4 x}}

\int e^{2 x} (2) d x

y^{^{'}} = y^{\frac{2}{3}}

\int \frac{4}{- 3 x} d x

\frac{d}{d x} (I n^{2})

f (x) = \frac{x}{( x ^{2} + 15 x + 50 )}

What is the solution for (dy)/(dx)+4y=-x ?
The solution for (dy)/(dx)+4y=-x is y=-(4x-1)/(16)+(c_{1})/(e^{4x)}