What is the solution for x^2y^{''}+3xy^'+y=0 ?

The solution for x^2y^{''}+3xy^'+y=0 is y=(c_{1})/x+(c_{2}ln(x))/x

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x^2y^{''}+3xy^'+y=0

x^{2} y^{^{''}} + 3 x y^{^{'}} + y = 0

y = \frac{c _{1}}{x} + \frac{c _{2} ln ( x )}{x}

Solution steps

x^{2} y^{''} (x) + 3 x y^{'} (x) + y = 0

Solve linear ODE:

y = \frac{c _{1}}{x} + \frac{c _{2} ln ( x )}{x}

y = \frac{c _{1}}{x} + \frac{c _{2} ln ( x )}{x}

s^{s}

\frac{d}{d x} (2 ln (x^{3}))

\frac{d y}{d x} (x^{2} + 1) + 7 x (y - 1) = 0

\int_{0}^{1} \frac{41}{x ^{5}} d x

What is the solution for x^2y^{''}+3xy^'+y=0 ?
The solution for x^2y^{''}+3xy^'+y=0 is y=(c_{1})/x+(c_{2}ln(x))/x