What is the derivative of f(x)=|x-1| ?

The derivative of f(x)=|x-1| is (x-1)/(|x-1|)

What is the first derivative of f(x)=|x-1| ?

The first derivative of f(x)=|x-1| is (x-1)/(|x-1|)

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derivative of

f (x) = ∣ x - 1 ∣

\frac{x - 1}{∣ x - 1 ∣}

Solution steps

\frac{d}{d x} (∣ x - 1 ∣)

Apply the chain rule:

\frac{x - 1}{∣ ( x - 1 ) ∣} \frac{d}{d x} (x - 1)

= \frac{x - 1}{∣ ( x - 1 ) ∣} \frac{d}{d x} (x - 1)

\frac{d}{d x} (x - 1) = 1

= \frac{x - 1}{∣ ( x - 1 ) ∣} \cdot 1

Simplify

= \frac{x - 1}{∣ x - 1 ∣}

\frac{\partial}{\partial y} (ln (x + 3 y))

\int \frac{x - 2}{x ^{2} - x} d x

\int_{0}^{2} 2^{x} d x

\int \frac{1}{3 x ^{2} + 1} d x

y d u + (2 y - u) d y = 0

What is the derivative of f(x)=|x-1| ?
The derivative of f(x)=|x-1| is (x-1)/(|x-1|)
What is the first derivative of f(x)=|x-1| ?
The first derivative of f(x)=|x-1| is (x-1)/(|x-1|)