What is the sum from n=1 to infinity of (-1/4)^n ?

The sum from n=1 to infinity of (-1/4)^n is converges

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sum from n=1 to infinity of (-1/4)^n

n = 1 \sum \infty (- \frac{1}{4})^{n}

converges

Solution steps

n = 1 \sum \infty (- \frac{1}{4})^{n}

Apply Series Ratio Test:

converges

= converges

\frac{d y}{d x} - \frac{y}{x} = 8 x e^{x}

y = 3 sin (x), y = e^{x}, x = 0, x = \frac{π}{2}

\frac{8 ^{8 t}}{t}

csc^{2} (2 x)

y = 5 x - 2 x^{2} - x

What is the sum from n=1 to infinity of (-1/4)^n ?
The sum from n=1 to infinity of (-1/4)^n is converges