What is the derivative of e^{mt}*sin(nt) ?

The derivative of e^{mt}*sin(nt) is 0

What is the first derivative of e^{mt}*sin(nt) ?

The first derivative of e^{mt}*sin(nt) is 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (e^{m t} \cdot sin (n t))

0

Solution steps

\frac{d}{d x} (e^{m t} sin (n t))

Treat

m, n, t

as a constant

Derivative of a constant:

\frac{d}{d x} (a) = 0

= 0

f (x) = 3 cos (2 ln (x))

x \frac{d y}{d x} + y = x

y^{^{'}} + 6 y = e^{4 t}, y (0) = 2

\int \frac{x ^{2}}{20 - 4 x + x ^{2}} d x

\frac{d}{d x} (0.5 sin^{2} (x) - x + 1)

What is the derivative of e^{mt}*sin(nt) ?
The derivative of e^{mt}*sin(nt) is 0
What is the first derivative of e^{mt}*sin(nt) ?
The first derivative of e^{mt}*sin(nt) is 0