What is area sin(x),sin(2x),[0, pi/3 ] ?

The answer to area sin(x),sin(2x),[0, pi/3 ] is 1/4

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area sin(x),sin(2x),[0, pi/3 ]

area

sin (x), sin (2 x), [0, \frac{π}{3}]

\frac{1}{4}

Decimal Notation

0.25

Solution steps

Apply the area formula:

\int_{0}^{\frac{π}{3}} ∣ sin (x) - sin (2 x) ∣ d x

Solve

\int_{0}^{\frac{π}{3}} ∣ sin (x) - sin (2 x) ∣ d x : \frac{1}{4}

The area is:

= \frac{1}{4}

f (x) = \frac{1}{x} - 2 x

\frac{d}{d x} (\frac{3}{4} x^{2} - 5 x^{3})

\int \frac{1}{- 2 x} d x

cos^{2} (25 t)

5 x - 2 x

What is area sin(x),sin(2x),[0, pi/3 ] ?
The answer to area sin(x),sin(2x),[0, pi/3 ] is 1/4