What is area x-1,sqrt(2x+6),[-2,4] ?

The answer to area x-1,sqrt(2x+6),[-2,4] is (2(7sqrt(14)-sqrt(2)))/3

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area x-1,sqrt(2x+6),[-2,4]

area

x - 1, 2 x + 6, [- 2, 4]

\frac{2 ( 7 14 - 2 )}{3}

Decimal Notation

16.51825 \dots

Solution steps

Apply the area formula:

\int_{- 2}^{4} x - 1 - 2 x + 6 d x

Solve

\int_{- 2}^{4} x - 1 - 2 x + 6 d x : \frac{2 ( 7 14 - 2 )}{3}

The area is:

= \frac{2 ( 7 14 - 2 )}{3}

\frac{d}{d x} (\frac{2 x}{( x ^{2} - 3 ) ^{3}})

3 y^{^{''}} - 16 y^{^{'}} + 5 y = 0, y (0) = - 3, y^{^{'}} (0) = 4

\frac{1}{( x - 4 ) ^{2}}

f (x) = (3 x^{2} + 6 x)^{3}

\int 0.06 x^{2} - 4.4 x + 60 d x

What is area x-1,sqrt(2x+6),[-2,4] ?
The answer to area x-1,sqrt(2x+6),[-2,4] is (2(7sqrt(14)-sqrt(2)))/3