What is the derivative of f(x)=17e^x-ex^e ?

The derivative of f(x)=17e^x-ex^e is 17e^x-e^2x^{e-1}

What is the first derivative of f(x)=17e^x-ex^e ?

The first derivative of f(x)=17e^x-ex^e is 17e^x-e^2x^{e-1}

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derivative of

f (x) = 17 e^{x} - e x^{e}

17 e^{x} - e^{2} x^{e - 1}

Solution steps

\frac{d}{d x} (17 e^{x} - e x^{e})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (17 e^{x}) - \frac{d}{d x} (e x^{e})

\frac{d}{d x} (17 e^{x}) = 17 e^{x}

\frac{d}{d x} (e x^{e}) = e^{2} x^{e - 1}

= 17 e^{x} - e^{2} x^{e - 1}

f (x) = \frac{x}{x + 2}

\frac{d y}{d t} = 9 t^{2}

x \to - 2 lim (3 x^{2} - 3 x - 8)

f (x) = 6 x - x^{2}, at x = - 1

f^{^{'}} (θ) = cos (θ) - sin (θ)

What is the derivative of f(x)=17e^x-ex^e ?
The derivative of f(x)=17e^x-ex^e is 17e^x-e^2x^{e-1}
What is the first derivative of f(x)=17e^x-ex^e ?
The first derivative of f(x)=17e^x-ex^e is 17e^x-e^2x^{e-1}