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Popular >

(dy)/(dt)=9t^2

Solution

\frac{d y}{d t} = 9 t^{2}

Solution

y = 3 t^{3} + c_{1}

Solution steps

\frac{d y}{d t} = 9 t^{2}

Substitute

\frac{d y}{d t}

with

y^{'} (t)

y^{^{'}} (t) = 9 t^{2}

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int 9 t^{2} d t

\int 9 t^{2} d t = 3 t^{3} + c_{1}

y = 3 t^{3} + c_{1}

Popular Examples

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f^'(θ)=cos(θ)-sin(θ)

f^{^{'}} (θ) = cos (θ) - sin (θ)

(\partial)/(\partial y)(4x^3y^3+4)

\frac{\partial}{\partial y} (4 x^{3} y^{3} + 4)

integral from-1 to 3 of |4-x^2|

\int_{- 1}^{3} 4 - x^{2} d x

Frequently Asked Questions (FAQ)

What is the solution for (dy)/(dt)=9t^2 ?
The solution for (dy)/(dt)=9t^2 is y=3t^3+c_{1}