What is the integral of ((y-2))/(y+3) ?

The integral of ((y-2))/(y+3) is -5ln|y+3|+y+C

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integral of ((y-2))/(y+3)

\int \frac{( y - 2 )}{y + 3} d y

- 5 ln ∣ y + 3 ∣ + y + C

Solution steps

\int \frac{y - 2}{y + 3} d y

\frac{y - 2}{y + 3} = - \frac{5}{y + 3} + 1

= \int - \frac{5}{y + 3} + 1 d y

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int \frac{5}{y + 3} d y + \int 1 d y

\int \frac{5}{y + 3} d y = 5 ln ∣ y + 3 ∣

\int 1 d y = y

= - 5 ln ∣ y + 3 ∣ + y

Add a constant to the solution

= - 5 ln ∣ y + 3 ∣ + y + C

\int_{0}^{0.6} 2 x e^{- x} d x

y^{^{'}} = 2 y

\frac{d y}{d x} = y^{\frac{1}{3}}

x^{2} + 11, at x = 5

t^{13 t}

What is the integral of ((y-2))/(y+3) ?
The integral of ((y-2))/(y+3) is -5ln|y+3|+y+C