What is the sum from n=1 to infinity of 3/(n^4) ?

The sum from n=1 to infinity of 3/(n^4) is converges

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sum from n=1 to infinity of 3/(n^4)

n = 1 \sum \infty \frac{3}{n ^{4}}

converges

Solution steps

n = 1 \sum \infty \frac{3}{n ^{4}}

Apply the constant multiplication rule:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= 3 \cdot n = 1 \sum \infty \frac{1}{n ^{4}}

Apply p-Series Test:

converges

= 3 converges

= converges

\frac{d}{d x} (\frac{1}{arctan ( x )})

h \to 0 lim (\frac{( 1 + h ) ^{2} - 1}{h})

x \to 1 lim (1 + 6 x^{2})

y = \frac{- 8 x}{x ^{2} + 1}, (1, - 4)

\int csc^{3} (e x) d x

What is the sum from n=1 to infinity of 3/(n^4) ?
The sum from n=1 to infinity of 3/(n^4) is converges