What is the derivative of C(x)=-9x^2+500x+110 ?

The derivative of C(x)=-9x^2+500x+110 is -18x+500

What is the first derivative of C(x)=-9x^2+500x+110 ?

The first derivative of C(x)=-9x^2+500x+110 is -18x+500

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derivative of

C (x) = - 9 x^{2} + 500 x + 110

- 18 x + 500

Solution steps

\frac{d}{d x} (- 9 x^{2} + 500 x + 110)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (9 x^{2}) + \frac{d}{d x} (500 x) + \frac{d}{d x} (110)

\frac{d}{d x} (9 x^{2}) = 18 x

\frac{d}{d x} (500 x) = 500

\frac{d}{d x} (110) = 0

= - 18 x + 500 + 0

Simplify

= - 18 x + 500

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What is the derivative of C(x)=-9x^2+500x+110 ?
The derivative of C(x)=-9x^2+500x+110 is -18x+500
What is the first derivative of C(x)=-9x^2+500x+110 ?
The first derivative of C(x)=-9x^2+500x+110 is -18x+500