What is the derivative of 2x^2+7x+4 ?

The derivative of 2x^2+7x+4 is 4x+7

What is the first derivative of 2x^2+7x+4 ?

The first derivative of 2x^2+7x+4 is 4x+7

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derivative of

2 x^{2} + 7 x + 4

4 x + 7

Solution steps

\frac{d}{d x} (2 x^{2} + 7 x + 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) + \frac{d}{d x} (7 x) + \frac{d}{d x} (4)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (7 x) = 7

\frac{d}{d x} (4) = 0

= 4 x + 7 + 0

Simplify

= 4 x + 7

\int x cos (3 π) x^{2} d x

10 + t^{2}

\frac{\partial}{\partial y} (6 x^{2})

\int \frac{6 + x ^{2}}{x} d x

(x + 1) (7 x + 2)

What is the derivative of 2x^2+7x+4 ?
The derivative of 2x^2+7x+4 is 4x+7
What is the first derivative of 2x^2+7x+4 ?
The first derivative of 2x^2+7x+4 is 4x+7