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Popular >

area f(x)=16-x^2,(1,4)

Solution

area

f (x) = 16 - x^{2}, (1, 4)

Solution

27

Solution steps

Apply the area formula:

\int_{1}^{4} 16 - x^{2} d x

Solve

\int_{1}^{4} 16 - x^{2} d x : 27

The area is:

= 27

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(9+y^2)dx+4xydy=0

(9 + y^{2}) d x + 4 x y d y = 0

tangent of y=8x+12-15e^x,(0,-3)tangent of

y = 8 x + 12 - 15 e^{x}, (0, - 3)

integral of (3+x)/(1+x^2)

\int \frac{3 + x}{1 + x ^{2}} d x

Frequently Asked Questions (FAQ)

What is area f(x)=16-x^2,(1,4) ?
The answer to area f(x)=16-x^2,(1,4) is 27