What is the derivative of 1-4x^2 ?

The derivative of 1-4x^2 is -8x

What is the first derivative of 1-4x^2 ?

The first derivative of 1-4x^2 is -8x

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\frac{d}{d x} (1 - 4 x^{2})

- 8 x

Solution steps

\frac{d}{d x} (1 - 4 x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) - \frac{d}{d x} (4 x^{2})

\frac{d}{d x} (1) = 0

\frac{d}{d x} (4 x^{2}) = 8 x

= 0 - 8 x

Simplify

= - 8 x

\int 64 - t^{2} d t

\frac{d}{d x} (- 6 e^{- x})

\int \frac{8}{x ^{2} - 36} d x

\frac{d}{d x} (e^{6} + ln (9))

f (x)^{8} x^{2} + 4 x - 7, x = - 3