What is the limit as x approaches 1 of (x^2+1)/(x+1) ?

The limit as x approaches 1 of (x^2+1)/(x+1) is 1

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limit as x approaches 1 of (x^2+1)/(x+1)

x \to 1 lim (\frac{x ^{2} + 1}{x + 1})

1

Solution steps

x \to 1 lim (\frac{x ^{2} + 1}{x + 1})

Plug in the value

x = 1

= \frac{1 ^{2} + 1}{1 + 1}

Simplify

= 1

f (x) = 80640 (2 x + 5)^{2}

f (x) = x^{2} - x

2 x x

y = x + tan (x), (π, π)

x \to 0 lim (ln (sinh (x)))

What is the limit as x approaches 1 of (x^2+1)/(x+1) ?
The limit as x approaches 1 of (x^2+1)/(x+1) is 1