What is the tangent of y=x+tan(x),(pi,pi) ?

The tangent of y=x+tan(x),(pi,pi) is y=2x-pi

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tangent of y=x+tan(x),(pi,pi)

tangent of

y = x + tan (x), (π, π)

y = 2 x - π

Solution steps

Find the slope of

y = x + tan (x) : \frac{d y}{d x} = 1 + sec^{2} (x)

Compute the slope of

y = x + tan (x)

(π, π) : m = 2

Find the line with slope m=

2

and passing through

(π, π) : y = 2 x - π

y = 2 x - π

x \to 0 lim (ln (sinh (x)))

\int \frac{4}{369} x^{3} d x

x \to 1 lim (3 x^{2} + 4)

y = x^{2} - 8, y = 8

\frac{d}{d x} (sin (π^{2}))

What is the tangent of y=x+tan(x),(pi,pi) ?
The tangent of y=x+tan(x),(pi,pi) is y=2x-pi