What is the (e^{-x/2})^' ?

The (e^{-x/2})^' is -1/2 e^{-x/2}

What is the first (e^{-x/2})^' ?

The first (e^{-x/2})^' is -1/2 e^{-x/2}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(e^{- \frac{x}{2}})^{^{'}}

- \frac{1}{2} e^{- \frac{x}{2}}

Solution steps

(e^{- \frac{x}{2}})^{'}

Apply the chain rule:

e^{- \frac{x}{2}} (- \frac{x}{2})^{'}

= e^{- \frac{x}{2}} (- \frac{x}{2})^{'}

(- \frac{x}{2})^{'} = - \frac{1}{2}

= e^{- \frac{x}{2}} (- \frac{1}{2})

Simplify

= - \frac{1}{2} e^{- \frac{x}{2}}

y^{^{'}} - y = 1, y (0) = 1

\int sin^{3} (18 x) cos^{3} (18 x) d x

\int \frac{8 x}{( 1 - x ^{2} ) ^{4}} d x

\frac{\partial}{\partial z} (\frac{4 x - 4 z}{y + 4 z})

y y^{^{'}} = x - 2 x^{3}