What is the solution for y^'+(2y)/t =(2cos(t^2))/t ?

The solution for y^'+(2y)/t =(2cos(t^2))/t is y=(sin(t^2))/(t^2)+(c_{1})/(t^2)

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y^'+(2y)/t =(2cos(t^2))/t

y^{^{'}} + \frac{2 y}{t} = \frac{2 cos ( t ^{2} )}{t}

y = \frac{sin ( t ^{2} )}{t ^{2}} + \frac{c _{1}}{t ^{2}}

Solution steps

y^{'} (t) + \frac{2 y}{t} = \frac{2 cos ( t ^{2} )}{t}

Solve linear ODE:

y = \frac{sin ( t ^{2} )}{t ^{2}} + \frac{c _{1}}{t ^{2}}

y = \frac{sin ( t ^{2} )}{t ^{2}} + \frac{c _{1}}{t ^{2}}

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What is the solution for y^'+(2y)/t =(2cos(t^2))/t ?
The solution for y^'+(2y)/t =(2cos(t^2))/t is y=(sin(t^2))/(t^2)+(c_{1})/(t^2)