What is (\partial ^2)/(\partial r\partial θ)(r(θ)*sin(θ)) ?

The answer to (\partial ^2)/(\partial r\partial θ)(r(θ)*sin(θ)) is sin(θ)+θcos(θ)

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(\partial ^2)/(\partial r\partial θ)(r(θ)*sin(θ))

\frac{\partial ^{2}}{\partial r \partial θ} (r (θ) \cdot sin (θ))

sin (θ) + θ cos (θ)

Solution steps

\frac{\partial ^{2}}{\partial r \partial θ} (r (θ) sin (θ))

\frac{\partial}{\partial r} (r θ sin (θ)) = θ sin (θ)

= \frac{\partial}{\partial θ} (θ sin (θ))

\frac{\partial}{\partial θ} (θ sin (θ)) = sin (θ) + θ cos (θ)

= sin (θ) + θ cos (θ)

y = 2 x^{4}, (- 2, 32)

x \to 2 lim (- x)

\frac{d}{d x} (\frac{5 x ^{2} + 25 x}{5 x})

\int 10 - x^{2} d x

\int (x e^{- x^{2}}) d x

What is (\partial ^2)/(\partial r\partial θ)(r(θ)*sin(θ)) ?
The answer to (\partial ^2)/(\partial r\partial θ)(r(θ)*sin(θ)) is sin(θ)+θcos(θ)