What is the integral of sqrt(2x+1) ?

The integral of sqrt(2x+1) is 1/3 (2x+1)^{3/2}+C

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integral of sqrt(2x+1)

\int 2 x + 1 d x

\frac{1}{3} (2 x + 1)^{\frac{3}{2}} + C

Solution steps

\int 2 x + 1 d x

Apply u-substitution

: \int \frac{u}{2} d u

= \int \frac{u}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int u d u

Apply the Power Rule

: \frac{2}{3} u^{\frac{3}{2}}

= \frac{1}{2} \cdot \frac{2}{3} u^{\frac{3}{2}}

Substitute back

u = 2 x + 1

= \frac{1}{2} \cdot \frac{2}{3} (2 x + 1)^{\frac{3}{2}}

Simplify

\frac{1}{2} \cdot \frac{2}{3} (2 x + 1)^{\frac{3}{2}} : \frac{1}{3} (2 x + 1)^{\frac{3}{2}}

= \frac{1}{3} (2 x + 1)^{\frac{3}{2}}

Add a constant to the solution

= \frac{1}{3} (2 x + 1)^{\frac{3}{2}} + C

\int 3^{x} sin (x) d x

\frac{\partial}{\partial y} (y cos (x ln (y)))

\int_{0}^{2} 1 + 3 x^{2} d x

6 x^{- 3}, at x = 5

\frac{x - y}{x + y}

What is the integral of sqrt(2x+1) ?
The integral of sqrt(2x+1) is 1/3 (2x+1)^{3/2}+C