What is (\partial)/(\partial x)(2y^3+4x) ?

The answer to (\partial)/(\partial x)(2y^3+4x) is 4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(2y^3+4x)

\frac{\partial}{\partial x} (2 y^{3} + 4 x)

4

Solution steps

\frac{\partial}{\partial x} (2 y^{3} + 4 x)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 y^{3}) + \frac{\partial}{\partial x} (4 x)

\frac{\partial}{\partial x} (2 y^{3}) = 0

\frac{\partial}{\partial x} (4 x) = 4

= 0 + 4

Simplify

= 4

\int \frac{2 - 8 x}{9 - 4 x ^{2}} d x

y = 2 x^{2} - 9 x + 7

\frac{d}{d x} (\frac{1}{2 cos ^{2} ( x )})

\int (x x + 2) d x

\frac{d}{d x} (2 x - 0.1 x^{2})

What is (\partial)/(\partial x)(2y^3+4x) ?
The answer to (\partial)/(\partial x)(2y^3+4x) is 4