What is laplacetransform e^{-2t-5} ?

The answer to laplacetransform e^{-2t-5} is 1/(e^5(s+2))

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laplacetransform e^{-2t-5}

laplace transform

e^{- 2 t - 5}

\frac{1}{e ^{5} ( s + 2 )}

Solution steps

L {e^{- 2 t - 5}}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= e^{- 5} L {e^{- 2 t}}

L {e^{- 2 t}} : \frac{1}{s + 2}

= e^{- 5} \frac{1}{s + 2}

Refine

e^{- 5} \frac{1}{s + 2} : \frac{1}{e ^{5} ( s + 2 )}

= \frac{1}{e ^{5} ( s + 2 )}

\frac{\partial}{\partial x} (y \cdot ln (x))

\frac{d}{d x} (s e^{- s x y (s, x)})

\int \frac{x + 1}{x ^{3} - x ^{2}} d x

\int_{0}^{π} sin^{2} (x) d x

\frac{\partial}{\partial x} (ln (4 - x^{2}))

What is laplacetransform e^{-2t-5} ?
The answer to laplacetransform e^{-2t-5} is 1/(e^5(s+2))