What is the derivative of h(g(x)k(x)) ?

The derivative of h(g(x)k(x)) is hkx^2

What is the first derivative of h(g(x)k(x)) ?

The first derivative of h(g(x)k(x)) is hkx^2

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derivative of

h (g (x) k (x))

hk x^{2}

Solution steps

\frac{d}{d g} (h gx k x)

Simplify

h gx k x : hk g x^{2}

= \frac{d}{d g} (hk g x^{2})

Treat

h, k, x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= hk x^{2} \frac{d g}{d g}

Apply the common derivative:

\frac{d g}{d g} = 1

= hk x^{2} \cdot 1

Simplify

= hk x^{2}

\frac{2}{3} (1 + x)^{\frac{3}{2}}

f (x) = 3 e^{x}, at x = 0

y^{^{'}} = - 5 y + 5 t^{2} + 2 t, y (0) = \frac{1}{3}

\int \frac{3}{4 - x ^{2}} d x

\frac{d}{d θ} (θ - sin (θ))

What is the derivative of h(g(x)k(x)) ?
The derivative of h(g(x)k(x)) is hkx^2
What is the first derivative of h(g(x)k(x)) ?
The first derivative of h(g(x)k(x)) is hkx^2