What is (\partial)/(\partial y)(e^{xyz^3}yz^3) ?

The answer to (\partial)/(\partial y)(e^{xyz^3}yz^3) is z^3(e^{xyz^3}xyz^3+e^{xyz^3})

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(\partial)/(\partial y)(e^{xyz^3}yz^3)

\frac{\partial}{\partial y} (e^{x y z^{3}} y z^{3})

z^{3} (e^{x y z^{3}} x y z^{3} + e^{x y z^{3}})

Solution steps

\frac{\partial}{\partial y} (e^{x y z^{3}} y z^{3})

Treat

x, z

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= z^{3} \frac{\partial}{\partial y} (e^{x y z^{3}} y)

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = e^{x y z^{3}}, g = y

= z^{3} (\frac{\partial}{\partial y} (e^{x y z^{3}}) y + \frac{\partial}{\partial y} (y) e^{x y z^{3}})

\frac{\partial}{\partial y} (e^{x y z^{3}}) = e^{x y z^{3}} x z^{3}

\frac{\partial}{\partial y} (y) = 1

= z^{3} (e^{x y z^{3}} x z^{3} y + 1 \cdot e^{x y z^{3}})

Simplify

= z^{3} (e^{x y z^{3}} x y z^{3} + e^{x y z^{3}})

\int x (a - b x^{2}) d x

f (x) = 2 x^{2} + x - 2, at x = 4

\int \frac{- 1600 x}{25 - x ^{2}} d x

\int \frac{1}{x 8 x + 81} d x

\frac{\partial}{\partial x} (x + e^{y})

What is (\partial)/(\partial y)(e^{xyz^3}yz^3) ?
The answer to (\partial)/(\partial y)(e^{xyz^3}yz^3) is z^3(e^{xyz^3}xyz^3+e^{xyz^3})