What is the tangent of f(x)=sqrt(7x-17),\at x=3 ?

The tangent of f(x)=sqrt(7x-17),\at x=3 is y= 7/4 x-13/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=sqrt(7x-17),\at x=3

tangent of

f (x) = 7 x - 17, at x = 3

y = \frac{7}{4} x - \frac{13}{4}

Solution steps

Find the tangent point:

(3, 2)

Find the slope of

f (x) = 7 x - 17 : \frac{df ( x )}{d x} = \frac{7}{2 7 x - 17}

Compute the slope of

f (x) = 7 x - 17

x = 3 : m = \frac{7}{4}

Find the line with slope m=

\frac{7}{4}

and passing through

(3, 2) : y = \frac{7}{4} x - \frac{13}{4}

y = \frac{7}{4} x - \frac{13}{4}

\frac{d}{d x} (6 x^{\frac{1}{3}} + 3 x^{\frac{4}{3}})

\int \frac{x + 1}{x} d x

(x^{2} - 2 x + 3)^{^{'}}

\int_{- 1}^{0} x^{3} d x

- \frac{32}{x ^{3}} + \frac{4}{x ^{2}}

What is the tangent of f(x)=sqrt(7x-17),\at x=3 ?
The tangent of f(x)=sqrt(7x-17),\at x=3 is y= 7/4 x-13/4