What is the derivative of sqrt(8-3x) ?

The derivative of sqrt(8-3x) is -3/(2sqrt(8-3x))

What is the first derivative of sqrt(8-3x) ?

The first derivative of sqrt(8-3x) is -3/(2sqrt(8-3x))

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\frac{d}{d x} (8 - 3 x)

- \frac{3}{2 8 - 3 x}

Solution steps

\frac{d}{d x} (8 - 3 x)

Apply the chain rule:

\frac{1}{2 8 - 3 x} \frac{d}{d x} (8 - 3 x)

= \frac{1}{2 8 - 3 x} \frac{d}{d x} (8 - 3 x)

\frac{d}{d x} (8 - 3 x) = - 3

= \frac{1}{2 8 - 3 x} (- 3)

Simplify

\frac{1}{2 8 - 3 x} (- 3) : - \frac{3}{2 8 - 3 x}

= - \frac{3}{2 8 - 3 x}

\frac{\partial}{\partial x} (x^{4} + y^{4} - 32 x + 4 y + 4)

\frac{d}{d x} (f (x) (x g (x)))

y^{^{'}} + \frac{1}{t} y = 3 cos (2 t)

\frac{d}{d x} (x^{2} cos (ln (x)))

x \to 0 + lim (x \cdot e^{\frac{1}{x}})

What is the derivative of sqrt(8-3x) ?
The derivative of sqrt(8-3x) is -3/(2sqrt(8-3x))
What is the first derivative of sqrt(8-3x) ?
The first derivative of sqrt(8-3x) is -3/(2sqrt(8-3x))