What is the derivative of x^4+4/3 x^3-4x^2 ?

The derivative of x^4+4/3 x^3-4x^2 is 4x^3+4x^2-8x

What is the first derivative of x^4+4/3 x^3-4x^2 ?

The first derivative of x^4+4/3 x^3-4x^2 is 4x^3+4x^2-8x

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\frac{d}{d x} (x^{4} + \frac{4}{3} x^{3} - 4 x^{2})

4 x^{3} + 4 x^{2} - 8 x

Solution steps

\frac{d}{d x} (x^{4} + \frac{4}{3} x^{3} - 4 x^{2})

Simplify

x^{4} + \frac{4}{3} x^{3} - 4 x^{2} : x^{4} + \frac{4 x ^{3}}{3} - 4 x^{2}

= \frac{d}{d x} (x^{4} + \frac{4 x ^{3}}{3} - 4 x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{4}) + \frac{d}{d x} (\frac{4 x ^{3}}{3}) - \frac{d}{d x} (4 x^{2})

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (\frac{4 x ^{3}}{3}) = 4 x^{2}

\frac{d}{d x} (4 x^{2}) = 8 x

= 4 x^{3} + 4 x^{2} - 8 x

\int (- 3 x + 2) e^{- x} d x

x \to 0 lim (\frac{7 e ^{x}}{x ^{5}})

\int 4 x^{2} - 2 d x

x \to + 1 lim (0)

\frac{x}{( x ^{2} - 9 ) \cdot x}

What is the derivative of x^4+4/3 x^3-4x^2 ?
The derivative of x^4+4/3 x^3-4x^2 is 4x^3+4x^2-8x
What is the first derivative of x^4+4/3 x^3-4x^2 ?
The first derivative of x^4+4/3 x^3-4x^2 is 4x^3+4x^2-8x