What is the solution for (d^2x)/(dt^2)+k^2x=0 ?

The solution for (d^2x)/(dt^2)+k^2x=0 is x=c_{1}cos(kt)+c_{2}sin(kt)

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(d^2x)/(dt^2)+k^2x=0

\frac{d ^{2} x}{d t ^{2}} + k^{2} x = 0

x = c_{1} cos (k t) + c_{2} sin (k t)

Solution steps

\frac{d ^{2} x}{d t ^{2}} + k^{2} x = 0

Solve linear ODE:

x = c_{1} cos (k t) + c_{2} sin (k t)

x = c_{1} cos (k t) + c_{2} sin (k t)

x \to 0 lim (\frac{1}{cos ( x )})

x \to 4 lim (\frac{5}{( x - 4 ) ^{2}})

\frac{d}{d x} (2 cos (x) - 3 ln (x) - 1)

\frac{d y}{d x}, y^{4} = 2 x

\int_{0}^{\infty} x y e^{- y x} d x

What is the solution for (d^2x)/(dt^2)+k^2x=0 ?
The solution for (d^2x)/(dt^2)+k^2x=0 is x=c_{1}cos(kt)+c_{2}sin(kt)