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Popular >

xy^'+2y-12=0

Solution

x y^{^{'}} + 2 y - 12 = 0

Solution

y = \frac{c _{1}}{x ^{2}} + 6

Solution steps

x y^{'} (x) + 2 y - 12 = 0

Solve separable ODE:

y = \frac{c _{1}}{x ^{2}} + 6

y = \frac{c _{1}}{x ^{2}} + 6

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Frequently Asked Questions (FAQ)

What is the solution for xy^'+2y-12=0 ?
The solution for xy^'+2y-12=0 is y=(c_{1})/(x^2)+6