What is the solution for y^'=(ty)/(t+1),y(4)=1 ?

The solution for y^'=(ty)/(t+1),y(4)=1 is y=(5e^{t-4})/(t+1)

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y^'=(ty)/(t+1),y(4)=1

y^{^{'}} = \frac{t y}{t + 1}, y (4) = 1

y = \frac{5 e ^{t - 4}}{t + 1}

Solution steps

y^{'} (t) = \frac{t y}{t + 1}

Solve separable ODE:

y = \frac{5 e ^{t - 4}}{t + 1}

y = \frac{5 e ^{t - 4}}{t + 1}

(x + y) d x + (3 x + 3 y - 4) d y = 0

\frac{d}{d x} (e^{- 4 x^{3} - 2 x + 4})

f (x) = 6 (ln (x + 1))

e^{x} - x^{7}

What is the solution for y^'=(ty)/(t+1),y(4)=1 ?
The solution for y^'=(ty)/(t+1),y(4)=1 is y=(5e^{t-4})/(t+1)