What is the sum from n=2 to infinity of 1/(n^3) ?

The sum from n=2 to infinity of 1/(n^3) is converges

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sum from n=2 to infinity of 1/(n^3)

n = 2 \sum \infty \frac{1}{n ^{3}}

converges

Solution steps

n = 2 \sum \infty \frac{1}{n ^{3}}

Apply p-Series Test:

converges

= converges

\int \frac{x}{5 + 4 x - x ^{2}} d x

\int_{1}^{\infty} x^{2} d x

f (x) = \frac{2 x ^{2} + 6 x + 6}{x + 1}

\frac{d y}{d x} = e^{4 y} sin (5 x)

\frac{\partial}{\partial x} (6 x + 4 y)

What is the sum from n=2 to infinity of 1/(n^3) ?
The sum from n=2 to infinity of 1/(n^3) is converges