What is the tangent of y=7e^xcos(x),(0,7) ?

The tangent of y=7e^xcos(x),(0,7) is y=7x+7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of y=7e^xcos(x),(0,7)

tangent of

y = 7 e^{x} cos (x), (0, 7)

y = 7 x + 7

Solution steps

Find the slope of

y = 7 e^{x} cos (x) : \frac{d y}{d x} = 7 (e^{x} cos (x) - e^{x} sin (x))

Compute the slope of

y = 7 e^{x} cos (x)

(0, 7) : m = 7

Find the line with slope m=

7

and passing through

(0, 7) : y = 7 x + 7

y = 7 x + 7

4 t^{3} - t^{2}, t^{4} + 2 t^{2}, 1 \leq t \leq 3

\int_{0}^{\infty} t e^{- 3 t} d t

x \to 6 lim (8 (x - 5) (x - 7))

\frac{\partial}{\partial x} (5 x y \cdot e^{- x^{2} y})

y = 4 x - x^{2}

What is the tangent of y=7e^xcos(x),(0,7) ?
The tangent of y=7e^xcos(x),(0,7) is y=7x+7