What is (\partial)/(\partial x)(2xyarcsin(yz)) ?

The answer to (\partial)/(\partial x)(2xyarcsin(yz)) is 2yarcsin(yz)

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(\partial)/(\partial x)(2xyarcsin(yz))

\frac{\partial}{\partial x} (2 x y arcsin (yz))

2 y arcsin (yz)

Solution steps

\frac{\partial}{\partial x} (2 x y arcsin (yz))

Treat

y, z

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 y arcsin (yz) \frac{\partial}{\partial x} (x)

Apply the common derivative:

\frac{\partial}{\partial x} (x) = 1

= 2 y arcsin (yz) \cdot 1

Simplify

= 2 y arcsin (yz)

\frac{1}{2 x} + 2 x

f (x) = (x + 2)^{x^{2} - 2 x + 1}

\int_{3}^{5} \frac{x}{x ^{2} - 2} d x

\int \frac{2 x + 2}{x ^{2} + 2 x - 1} d x

What is (\partial)/(\partial x)(2xyarcsin(yz)) ?
The answer to (\partial)/(\partial x)(2xyarcsin(yz)) is 2yarcsin(yz)