What is the derivative of 8xe^x ?

The derivative of 8xe^x is 8(e^x+e^xx)

What is the first derivative of 8xe^x ?

The first derivative of 8xe^x is 8(e^x+e^xx)

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derivative of

8 x e^{x}

8 (e^{x} + e^{x} x)

Solution steps

\frac{d}{d x} (8 x e^{x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 8 \frac{d}{d x} (x e^{x})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = e^{x}

= 8 (\frac{d x}{d x} e^{x} + \frac{d}{d x} (e^{x}) x)

\frac{d x}{d x} = 1

\frac{d}{d x} (e^{x}) = e^{x}

= 8 (1 \cdot e^{x} + e^{x} x)

Simplify

= 8 (e^{x} + e^{x} x)

\int \frac{x}{x - 7} d x

x^{3} - 3 x + 1

\int \frac{3 x ^{2}}{x ^{3} + 7} d x

\frac{\partial}{\partial x} (ln (cos (x)))

\frac{( x ^{2} )}{x ^{2} + 27}

What is the derivative of 8xe^x ?
The derivative of 8xe^x is 8(e^x+e^xx)
What is the first derivative of 8xe^x ?
The first derivative of 8xe^x is 8(e^x+e^xx)