What is the solution for y^{''}+8y^'+32y=0,y(0)=0,y^'(0)=0 ?

The solution for y^{''}+8y^'+32y=0,y(0)=0,y^'(0)=0 is y=0

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y^{''}+8y^'+32y=0,y(0)=0,y^'(0)=0

y^{^{''}} + 8 y^{^{'}} + 32 y = 0, y (0) = 0, y^{^{'}} (0) = 0

y = 0

Solution steps

y^{''} (t) + 8 y^{'} (t) + 32 y = 0

Solve linear ODE:

y = 0

y = 0

\int \frac{- x}{1 - x ^{2}} d x

\frac{d}{d x} (c x e^{- 2 x})

\frac{d}{d x} (\frac{2 sin ( x )}{x})

x \to 2 lim (\frac{x ^{2} - 4}{x ^{2} - 3 - 1})

\frac{\partial}{\partial z} (y z^{2})

What is the solution for y^{''}+8y^'+32y=0,y(0)=0,y^'(0)=0 ?
The solution for y^{''}+8y^'+32y=0,y(0)=0,y^'(0)=0 is y=0