What is the tangent of y=(7x)/(x-3),(6,14) ?

The tangent of y=(7x)/(x-3),(6,14) is y=-7/3 x+28

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tangent of y=(7x)/(x-3),(6,14)

tangent of

y = \frac{7 x}{x - 3}, (6, 14)

y = - \frac{7}{3} x + 28

Solution steps

Find the slope of

y = \frac{7 x}{x - 3} : \frac{d y}{d x} = - \frac{21}{( x - 3 ) ^{2}}

Compute the slope of

y = \frac{7 x}{x - 3}

(6, 14) : m = - \frac{7}{3}

Find the line with slope m=

- \frac{7}{3}

and passing through

(6, 14) : y = - \frac{7}{3} x + 28

y = - \frac{7}{3} x + 28

(x)^{2}

\frac{\partial}{\partial y} (y + x)

y = \frac{1}{( 9 x ^{3} )}, 1, 100

20 y^{^{''}} + 4 y^{^{'}} + y = 0

What is the tangent of y=(7x)/(x-3),(6,14) ?
The tangent of y=(7x)/(x-3),(6,14) is y=-7/3 x+28