What is the derivative of-6\sqrt[3]{x^2} ?

The derivative of-6\sqrt[3]{x^2} is -(4x)/((x^2)^{2/3)}

What is the first derivative of-6\sqrt[3]{x^2} ?

The first derivative of-6\sqrt[3]{x^2} is -(4x)/((x^2)^{2/3)}

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derivative of

- \frac{4 x}{( x ^{2} ) ^{\frac{2}{3}}}

Solution steps

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

Apply the chain rule:

\frac{1}{3 ( x ^{2} ) ^{\frac{2}{3}}} \frac{d}{d x} (x^{2})

= \frac{1}{3 ( x ^{2} ) ^{\frac{2}{3}}} \frac{d}{d x} (x^{2})

\frac{d}{d x} (x^{2}) = 2 x

= - 6 \cdot \frac{1}{3 ( x ^{2} ) ^{\frac{2}{3}}} \cdot 2 x

Simplify

- 6 \cdot \frac{1}{3 ( x ^{2} ) ^{\frac{2}{3}}} \cdot 2 x : - \frac{4 x}{( x ^{2} ) ^{\frac{2}{3}}}

= - \frac{4 x}{( x ^{2} ) ^{\frac{2}{3}}}

(x)^{2}

\frac{\partial}{\partial y} (y + x)

y = \frac{1}{( 9 x ^{3} )}, 1, 100

20 y^{^{''}} + 4 y^{^{'}} + y = 0

(x + x)^{^{'}}

What is the derivative of-6\sqrt[3]{x^2} ?
The derivative of-6\sqrt[3]{x^2} is -(4x)/((x^2)^{2/3)}
What is the first derivative of-6\sqrt[3]{x^2} ?
The first derivative of-6\sqrt[3]{x^2} is -(4x)/((x^2)^{2/3)}