What is (\partial)/(\partial x)(xy^2-2x) ?

The answer to (\partial)/(\partial x)(xy^2-2x) is y^2-2

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(\partial)/(\partial x)(xy^2-2x)

\frac{\partial}{\partial x} (x y^{2} - 2 x)

y^{2} - 2

Solution steps

\frac{\partial}{\partial x} (x y^{2} - 2 x)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x y^{2}) - \frac{\partial}{\partial x} (2 x)

\frac{\partial}{\partial x} (x y^{2}) = y^{2}

\frac{\partial}{\partial x} (2 x) = 2

= y^{2} - 2

\int \frac{14}{x ^{2} + 1} d x

\frac{d}{d x} (e^{f (x)})

y = 10 x sin (x), (\frac{π}{2}, 5 π)

y^{^{'}} - 5 y = x

\int sec^{4} (x t a) n^{3} x d x

What is (\partial)/(\partial x)(xy^2-2x) ?
The answer to (\partial)/(\partial x)(xy^2-2x) is y^2-2