What is the integral of (14)/(x^2+1) ?

The integral of (14)/(x^2+1) is 14arctan(x)+C

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integral of (14)/(x^2+1)

\int \frac{14}{x ^{2} + 1} d x

14 arctan (x) + C

Solution steps

\int \frac{14}{x ^{2} + 1} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 14 \cdot \int \frac{1}{x ^{2} + 1} d x

Use the common integral:

\int \frac{1}{x ^{2} + 1} d x = arctan (x)

= 14 arctan (x)

Add a constant to the solution

= 14 arctan (x) + C

\frac{d}{d x} (e^{f (x)})

y = 10 x sin (x), (\frac{π}{2}, 5 π)

y^{^{'}} - 5 y = x

\int sec^{4} (x t a) n^{3} x d x

\int sin (θ) cos (θ) d θ

What is the integral of (14)/(x^2+1) ?
The integral of (14)/(x^2+1) is 14arctan(x)+C