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Popular >

y^'=y^2+xy^2

Solution

y^{^{'}} = y^{2} + x y^{2}

Solution

y = - \frac{2}{2 x + x ^{2} + c _{1}}

Solution steps

y^{'} (x) = y^{2} + x y^{2}

Solve separable ODE:

y = - \frac{2}{2 x + x ^{2} + c _{1}}

y = - \frac{2}{2 x + x ^{2} + c _{1}}

Popular Examples

integral of 7/(x(x^4+6))

\int \frac{7}{x ( x ^{4} + 6 )} d x

sum from k=1 to infinity of 1/(2^k)

k = 1 \sum \infty \frac{1}{2 ^{k}}

3x+y-2+(dy)/(dx)(x-1)=0

3 x + y - 2 + \frac{d y}{d x} (x - 1) = 0

sum from n=0 to infinity of 1/(2n+1)

n = 0 \sum \infty \frac{1}{2 n + 1}

integral of 1/(1+4x^2+4x^4)

\int \frac{1}{1 + 4 x ^{2} + 4 x ^{4}} d x

Frequently Asked Questions (FAQ)

What is the solution for y^'=y^2+xy^2 ?
The solution for y^'=y^2+xy^2 is y=-2/(2x+x^2+c_{1)}